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0=-4.9x^2-19.6x+0.50
We move all terms to the left:
0-(-4.9x^2-19.6x+0.50)=0
We add all the numbers together, and all the variables
-(-4.9x^2-19.6x+0.50)=0
We get rid of parentheses
4.9x^2+19.6x-0.50=0
We add all the numbers together, and all the variables
4.9x^2+19.6x-0.5=0
a = 4.9; b = 19.6; c = -0.5;
Δ = b2-4ac
Δ = 19.62-4·4.9·(-0.5)
Δ = 393.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19.6)-\sqrt{393.96}}{2*4.9}=\frac{-19.6-\sqrt{393.96}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19.6)+\sqrt{393.96}}{2*4.9}=\frac{-19.6+\sqrt{393.96}}{9.8} $
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